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olganol [36]
3 years ago
7

What is the sum of the probabilities of the favorable outcomes and the unfavorable outcomes, p(x=1)+p(x≠1)p(x=1)+p(x≠1)?

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

What's the sample space? Are we talking about rolling a die or what?


Anyway, if we call the probability p(x=1) = x, then p(x\neq 1) = 1-x


So, the expression becomes


x + (1-x)x + (1-x) = x + x - x^2 + 1 - x = -x^2+x+1

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