Answer:
See below
Step-by-step explanation:
a = 15 sqrt 2 sin 45
= 15 sqrt 2 * sqrt( 2 ) /2 = 15 * 2 /2 = 15
sin 60 = a/c
sqrt(3)/2 = 15/c
c = 15 / ( sqrt(3)/2) = 30 / sqrt 3 = 30 sqrt 3 /3 = 10 sqrt 3
Answer:
The standard deviation of weight for this species of cockroaches is 4.62.
Step-by-step explanation:
Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
To find : What is the approximate standard deviation of weight for this species of cockroaches?
Solution :
We have given,
Mean 
The sample mean x=55
A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
i.e. P(X>55)=14%=0.14
The total probability needs to sum up to 1,



The z-score value of 0.86 using z-score table is z=1.08.
Applying z-score formula,

Where,
is standard deviation
Substitute the values,





The standard deviation of weight for this species of cockroaches is 4.62.
Answer:
4x-20
Step-by-step explanation:
Answer: 50
Step-by-step explanation: all you have to do to find the perimeter is add all of the sides. I got 50 by adding these numbers.
Answer:
Step-by-step explanation:
and
and we are told that C is 6cm longer than A. That means that C = A + 6.
We are going to cross multiply each one of those ratios. The first one gives us
4A = 3B and the second one gives us
9B = 8C. But since C = A + 6, then
9B = 8(A + 6) and
9B = 8A + 48 and
Now we will solve the first equation above for A:
If 4A = 3B, then
and will use that as a sub for A in the second equation:
and
9B = 6B + 48 and
3B = 48 so
B = 16.
Now that we know B, we can use it to solve for A:
4A = 3(16) and
4A = 48 so
A = 12.
Then we can use that all the way back in the expression we set up for C:
C = A + 6 so
C = 12 + 6 so
C = 18
12 + 16 + 18 is the length of the string: 46cm