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2 years ago

Which of the following numbers is a power of ten?

Mathematics

2 answers:

Sloan [31]2 years ago

4 0

A. 20^10= 20,000 it repeats its self 10 times

Vinil7 [7]2 years ago

3 0

C.) 0.0001 is a power of ten

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What is the least common denominator of 2/6 and 7/8

Olegator [25]

Answer:

Therefore the least common denominator is 24.

Step-by-step explanation:

2/6 = 8/24

7/8 = 21/24

No more explanation.

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1 year ago

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When a number is doubled, the result is 48. What is the number

ddd [48]

The number u looking for is 28

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State a reason why a number does not belong with the others. <br> 32 64<br> 81 144

KiRa [710]

Answer : 81 because it is the only one that is not a multiple of 4

Step-by-step explanation:

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2 years ago

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Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago

A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for

klio [65]

Answer:

The rate is $\frac{2}{5}$ degree per hour.

Step-by-step explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose $\frac{1}{10}$ degree every $\frac{1}{4}$ hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every $\frac{1}{4}$ hour the temperature of a compound rose $\frac{1}{10}$ degree

To get the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

$r=\dfrac{\frac{1}{10}}{\frac{1}{4}}$ degree

$r=\dfrac{4}{10}$ degree/hr

$r=\dfrac{2}{5}$ degree/hr

Therefore, the rate is $\frac{2}{5}$ degree per hour.

5 0

2 years ago