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iragen [17]
3 years ago
6

A car manufacturer is concerned that dealers conceal unhappy customers by keeping them out of surveys conducted by the factory.

The manufacturer suspects that certain dealers enter incorrect addresses for dissatisfied customers so that they do not receive the satisfaction survey that is mailed by the manufacturer. If a current survey of the 65 customers at a dealership indicates​ 55% rate its service as exceptionally​ good, can the manufacturer estimate the proportion of all customers at this dealership who feel that its service is exceptionally​ good? Can it estimate the proportion at other​ dealerships?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

Yes, the manufacturer can estimate the proportion of all customers at this dealership who feel that its service is exceptionally​ good.

No, the manufacturer cannot estimate, the proportion of customers who rated the service as exceptionally good, about the other dealerships.

Step-by-step explanation:

A sample of 65 customers from a dealership is selected and it is determined that 55% of the customers rated the service as exceptionally good.

According to the central limit theorem if a large random sample selected from an unknown population then the sampling distribution of sample proportion (\hat p) follows a normal distribution.

Then the population proportion can be estimated by the sample proportion value.

That is, p=\hat p=0.55.

Thus, the manufacturer can estimate the proportion of all customers at this dealership who feel that its service is exceptionally​ good using the sample proportion value of \hat p=0.55.

Since the sample is selected from a specific dealership, he cannot estimate, the proportion of customers who rated the service as exceptionally good, about the other dealerships.

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Step-by-step explanation:

It is always a good idea to start by defining variables in such a problem. Here, we can let x represent the number of calling minutes, and y represent the number of data minutes. The the total number of minutes used is ...

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