Answer:
84,6km/h
Step-by-step explanation:
the whole journey was
in the first part the car travels 50km, in the second part 120km and in the third part we can find it with a simple rule of three
90km--->60 min
X<--------35min= 52.5 km the car made in the last part
50km+120km+52,5km=222.5km was all the journey
and he made it in:
- the last part in 35min,
- in the second part we know that the car was going at 80km/h and that he made 120km so:
80km--->60 min
120km--->90 min
- in the first part we know that the car was going at 25m/s and he made 50km. 25m/s*1km/1000m*3600s/1h= we obtain the speed in km/h=90km/h
90km---->60min
50km---->x=33,333 min
The whole journey last 33,333min+90min+35min=158.333min
if we express that in hour = 158.333min*1hr/60min=2.63
the car made 222.5km in 2.63 hour
so the average speed was
222.5---->2.63hr
X--------1hr=84,6
the average speed was 84,6km/h
It would be a negative number due to the fact that there are three negative numbers. A negative times a negative makes a positive, so because there are three it means the negative won't cancel out.
Answer:
48128m^3
Step-by-step explanation:
Given data
For the building
L=64m
W= 6m
H= 36m
The volume is
V= LWH/3
V=64*64*36/3
V=147456/3
V=49152m^3
For the off-Cut
L=16m
W= 16m
H= 12m
The volume is
V= LWH/3
V=16*16*12/3
V=3072/3
V=1024m^3
Hence the volume of the truncated part/Building
= Volume of building-volume of off-cut
=49152-1024
=48128m^3
Answer:
3.4, 3.7, 3.8
Step-by-step explanation:
Answer:
C = 9.5 + 1.25t
Step-by-step explanation:
C = 9.5 + 1.25t
16 = 9.5 + 1.25t
6.5 = 1.25t
6.5/1.25 = t
5.2 = t
you cant have 0.2 toppings so 5 is the max number of toppings Jonas can have
