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3 years ago

What is three blus six equal to

Mathematics

2 answers:

gavmur [86]3 years ago

5 0

Answer:

Three plus six: 3 * 6

When we multiply x*y, we are summing x times the same number: y ory times the same number.(x)

In our case, we are summing three times six, so: 6 + 6 + 6 = 18

We could also say we are summing six times three: 3 + 3 + 3 + 3 + 3 + 3 = 18

Nowwe can say that 6 * 3 = 18

lorasvet [3.4K]3 years ago

3 0

18
I hope this helps!!!!!!!!!!!

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What is the gcf of 14 and 22

Phantasy [73]

The multiples of 14 are 1,2,7,14
the multiples of 22 are 1,2,11,22
Therefore 2 is the GCF

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4 years ago

Deon has to buy all the butter she needs to make 60 biscuits. She buys the butter in 250 g packs. (b) How many packs of butter d

Vikki [24]

Answer:

200g of sugar, 600g of flour, 400g of butter

Step-by-step explanation:

50g sugar = 15 biscuits

3 x 50g = flour --) 150g = flour

2 x 50g = butter --) 100g = butter

60/15 = 4; 4 times as much

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3 years ago

I honestly dont know the answer for this

babunello [35]

The picture is blurry

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3 years ago

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify given limit.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

Step 2: Find Limit

Let's start out by directly evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have evaluated the given limit.

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Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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2 years ago

Whats a linear function

slega [8]

Answer:

A Linear Function is any function that graphs to any straight line. It can be consist of one or 2 or more variables but the degree or the exponent value of the variable shouldn't be greater than 1. it can be 0 but not greater than one .

Step-by-step explanation:

f(x)= y= a +bx , is the example of linear fucntion where the variable x has the exponent value of 1 ,

but the function f(x)= y= a+bx^2 is not a linear function because the exponent value of variable x is 2 .

Also if the Value of Exponent of the variable is in negative, that will be also a non linear function .

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3 years ago

What is three blus six equal to ​

What is three blus six equal to