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3 years ago

14

If two sides of a triangle are 5 and 7 inches longer than the third side and the perimeter measures 21, find the length of each

side of the triangle

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

Hello

x
x +5
x + 7

x + x + 5 + x + 7 = 21
3 x = 21 - 12
3 x = 9
x = 3

3 , 5 et 7 pouces

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sweet [91]

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Let t as y² + 5y .

${y}^{2} + 5y = t$

Rewrite the equation :

$t - \frac{36}{t} = 0 \\$

Multiply sides by t

$t \times (t - \frac{36}{t} ) = t \times 0 \\$

${t}^{2} - 36 = 0$

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$t = ± \: 6$

_________________________________

So :

${y}^{2} + 5y = 6$

Subtract sides 6

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$y = - 6 \: \: or \: \: y = 1$

##############################

${y}^{2} +5y = - 6$

$No \: \: solution$

_________________________________

Thus (( y = 1 )) and (( y = - 6 )) are the roots of the equation .

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