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Reil [10]
3 years ago
14

If two sides of a triangle are 5 and 7 inches longer than the third side and the perimeter measures 21, find the length of each

side of the triangle
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0
Hello

x
x +5 
x + 7

x + x + 5 + x + 7 = 21 
3 x = 21 - 12
3 x = 9
x = 3 

3 , 5 et 7 pouces
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6. Solve by factoring: 2x²-11x+14=0
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Step-by-step explanation:

Solve 2x^2-11x+14=0 give me 2 ways to get the 2 values of x?

The first way is to make factors by middle-term splitting. You get (x-2)(2x-7)=0, so the solution is x=2,7/2.

The other way is to use the formula for the solution of roots. Roots= (-b+ rootD)/2a, (-b-rootD)/2a, if the equation is of the form ax^2+bx+c=0. Here D is the discriminant. D=b^2-4ac

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Lets assume your equation is of the form ax^2+ bx + c =0

First method :

By breaking 'b' factor of x into two parts using factors of 'ac' ( a *c)

like 2* 14 = 28 = 7* 4 ( b is 11 which could be splitted in values 7 and 4)

equation becomes 2x^2 -4x-7x+14 = 0

take out common factors 2x(x-2) -7 (x-2) = 0

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Second method:

make equation in the form of (x+h)^ 2 - k = 0 ; then x+h = +sqrt(k) and -sqrt(k)

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