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mixer [17]
3 years ago
5

If a company must expand capacity to accept a special order, it is likely that there will be an increase in unit variable costs.

an increase in fixed costs. an increase in variable and fixed costs per unit. no increase in fixed costs.
Business
1 answer:
Lelechka [254]3 years ago
6 0

Answer:

If a company must expand capacity to accept a special order, it is likely that there will be an increase in fixed costs.

Explanation:

The fixed costs are the part of the total costs of production that remain constant during a given reference quantity in a certain period. These include, for example, depreciation of fixed assets or rental or interest expenses. Since fixed costs are incurred regardless of the application quantity (short-term), they cannot be apportioned to the unit costs according to the cause.

In the present case, given that the company must expand its capacity to take the special order, it means that all of its production factors are totally devoted to production, so that in order to produce a greater quantity of goods, the productive factors must be increased, which are part of the fixed production costs that the company has. Therefore, as the costs of production are altered, there will be an increase in fixed costs.

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Answer:

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  • The best combination is 1 hour of working problems + 3 hours of reading

Explanation:

To get the <em><u>marginal gain</u></em> we subtract from the latest hour, in this case the second hour (140), the production from the previous hour (80). 140-80=60. <em>It's always the same, the latest minus the previous one.</em>

So let's do the same for the fourth hour:

Noon................200 problems

minus

11:00 AM..........180 problems

200-180= 20 problems

Now to know how many hours he should spend working on problems and reading, let's compare:

An hour of reading equals to 70 problems made; (because working on 70 problems raises a student’s exam score by about the same amount as reading the textbook for 1 hour).

hours of working problems         problems solved

0............................................................0

1.............................................................80

2............................................................140

3............................................................180

hours reading                    problems equivalent to hours read

4...............................................(4*70)=280

3...............................................(3*70)=210

2...............................................(2*70)=140

1................................................(1*70)=70

finally let's add up the two combinations (0 and 4, 1 and 3, 2 and 2, 3 and 1)

0 and 4_______________0+280= 280

1 and 3________________80+210=290

2 and 2_______________140+140=280

3 and 1________________180+70=250

<em>And the best combination is 1 hour of working problems + 3 hours of reading=</em><em>290</em>

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