1 3/9 but if reduce to lowest term than 1 1/3
To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
A right rectangular pyramid when sliced vertically, the shape of the cross-section is known as Triangle.
<h3>What is A triangle?</h3>
This is known to be a kind of shape that is said to be in a closed form and it is also known to be a 2-dimensional shape that has 3 sides, 3 angles, and also 3 vertices.
Note that when the when the right rectangular pyramid is sliced vertically (down) by a plane passing through the of the pyramid, the new shape of the cross-section is a triangle.
See full question below
A right rectangular pyramid is sliced vertically (down) by a plane passing through the of the pyramid. What is the shape of the cross-section?
A. Rectangle
B. Pyramid
C. Triangle
D. Trapezoid
See full question below
Learn more about triangle from
brainly.com/question/17335144
#SPJ1
Answer:
P4200
Step-by-step explanation:
SI=PRT/100
P=Principal which is P10500
R=Rate which is 20%
T=Time which is 2 years
So SI= 10500×20×2/100
=P4200
Answer:
![A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36](https://tex.z-dn.net/?f=A%20%3D%20%5Cint%5Climits%5E3__-3%7D%7B9%7D-%7Bx%5E%7B2%7D%7D%20%5C%2C%20dx%20%3D%2036)
Step-by-step explanation:
The equations are:
![y = x^{2} + 2x + 3](https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B2%7D%20%2B%202x%20%2B%203)
![y = 2x + 12](https://tex.z-dn.net/?f=y%20%3D%202x%20%2B%2012)
The two graphs intersect when:
![x^{2} + 2x + 3 = 2x + 12](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%202x%20%2B%203%20%3D%202x%20%2B%2012)
![x^{2} = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D%200)
![x_{1} = 3\\x_{2} = -3](https://tex.z-dn.net/?f=x_%7B1%7D%20%20%3D%203%5C%5Cx_%7B2%7D%20%20%3D%20-3)
To find the area under the curve for the first equation:
![A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx](https://tex.z-dn.net/?f=A_%7B1%7D%20%3D%20%5Cint%5Climits%5E3__-3%7D%7Bx%5E%7B2%7D%20%2B%202x%20%2B%203%7D%20%5C%2C%20dx)
To find the area under the curve for the second equation:
![A_{2} = \int\limits^3__-3}{2x + 12} \, dx](https://tex.z-dn.net/?f=A_%7B2%7D%20%3D%20%5Cint%5Climits%5E3__-3%7D%7B2x%20%2B%2012%7D%20%5C%2C%20dx)
To find the total area:
![A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx](https://tex.z-dn.net/?f=A%20%3D%20A_%7B2%7D%20-A_%7B1%7D%20%3D%20%5Cint%5Climits%5E3__-3%7D%7B2x%20%2B%2012%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E3__-3%7D%7Bx%5E%7B2%7D%20%2B%202x%20%2B%203%7D%20%5C%2C%20dx)
Simplifying the equation:
![A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx](https://tex.z-dn.net/?f=A%20%3D%20%5Cint%5Climits%5E3__-3%7D%7B2x%20%2B%2012%7D-%28%7Bx%5E%7B2%7D%20%2B%202x%20%2B%203%7D%29%20%5C%2C%20dx%20%3D%20%5Cint%5Climits%5E3__-3%7D%7B9%7D-%7Bx%5E%7B2%7D%7D%20%5C%2C%20dx)
Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).