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elena-14-01-66 [18.8K]
3 years ago
8

Drag the symbol to complete the solution to this inequalities​

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer:

x ≤ 13.2.

Step-by-step explanation:

Hope this helps

dezoksy [38]3 years ago
3 0

Answer:

x ≤ 13.2.

Step-by-step explanation:

6  ≥  x/2.2

Multiply both sides by 2.2:

6 * 2.2 ≥ x

x ≤ 13.2.

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. Kay is shown on the number line below what’s the process is best described as a value represented by point k
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4 years ago
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Solve the given inequality :
tigry1 [53]

Answer:

x < -5  or  x = 1  or  2 < x < 3  or  x > 3

Step-by-step explanation:

Given <u>rational inequality</u>:

\dfrac{(x-1)^2(x-2)^3}{(x^2-5x+6)^2(x+5)}\geq 0

\textsf{Factor }(x^2-5x+6):

\implies x^2-2x-3x+6

\implies x(x-2)-3(x-2)

\implies (x-3)(x-2)

Therefore:

\dfrac{(x-1)^2(x-2)^3}{(x-3)^2(x-2)^2(x+5)}\geq 0

Find the roots by solving f(x) = 0  (set the numerator to zero):

\implies (x-1)^2(x-2)^3=0

\implies (x-1)^2=0\implies x=1

\implies (x-2)^3=0 \implies x=2

Find the restrictions by solving f(x) = <em>undefined  </em>(set the denominator to zero):

\implies (x-3)^2(x-2)^2(x+5)=0

\implies (x-3)^2=0 \implies x=3

\implies (x-2)^2=0 \implies x=2

\implies (x+5)=0 \implies x=-5

Create a sign chart, using closed dots for the <u>roots</u> and open dots for the <u>restrictions</u> (see attached).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Test values:  -6, 0, 1.5, 2.5, 4

For each test value, determine if the function is positive or negative:

f(-6)=\dfrac{(-6-1)^2(-6-2)^3}{(-6-3)^2(-6-2)^2(-6+5)}=\dfrac{(+)(-)}{(+)(+)(-)}=+

f(0)=\dfrac{(0-1)^2(0-2)^3}{(0-3)^2(0-2)^2(0+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-

f(1.5)=\dfrac{(1.5-1)^2(1.5-2)^3}{(1.5-3)^2(1.5-2)^2(1.5+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-

f(2.5)=\dfrac{(2.5-1)^2(2.5-2)^3}{(2.5-3)^2(2.5-2)^2(2.5+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+

f(4)=\dfrac{(4-1)^2(4-2)^3}{(4-3)^2(4-2)^2(4+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+

Record the results on the sign chart for each region (see attached).

As we need to find the values for which f(x) ≥ 0, shade the appropriate regions (zero or positive) on the sign chart (see attached).

Therefore, the solution set is:

x < -5  or  x = 1  or  2 < x < 3  or  x > 3

As interval notation:

(- \infty,-5) \cup x=1 \cup (2,3) \cup(3,\infty)

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2 years ago
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How to solve this equation 5x-4-7x=4
elixir [45]

Answer:

x= -4

Step-by-step explanation:

Simplifying

5x + -4 = 7x + 4

Solving

-4 + 5x = 4 + 7x

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.

-4 + 5x + -7x = 4 + 7x + -7x

Combine like terms: 5x + -7x = -2x

-4 + -2x = 4 + 7x + -7x

Combine like terms: 7x + -7x = 0

-4 + -2x = 4 + 0

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Add '4' to each side of the equation.

-4 + 4 + -2x = 4 + 4

Combine like terms: -4 + 4 = 0

0 + -2x = 4 + 4

-2x = 4 + 4

Combine like terms: 4 + 4 = 8

-2x = 8

Divide each side by '-2'.

x = -4

Simplifying

x = -4

3 0
3 years ago
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