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34kurt
3 years ago
5

Item 12

Mathematics
1 answer:
katovenus [111]3 years ago
6 0
Y=25(1.025)^x

Rate: r=1.025-1
r=0.025>0 (positive), then the function is increasing
r=0.025*100%
r=2.5%

Answer: Second option: Increasing by 2.5%
You might be interested in
a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
1 year ago
Is the answer 62 help plz
Elza [17]

Answer:

35

Step-by-step explanation:

You have to add up the two angles that it gives you which are 90 and 55. That'll equal 145. Since all the angles added together in a triangle are supposed to equal 180, you subtract 145 from 180 to get your answer of 35.

6 0
3 years ago
Solve the equation. 5/9d=9/10
astra-53 [7]
D would equal 50/81 I think?
6 0
2 years ago
I don’t understand this can someone help?!
kolezko [41]

Answer:do h just want answer or explanation

Step-by-step explanation:?

5 0
3 years ago
A passenger plane travels at about 7.62 x 10^2 feet per second. The plane takes 1.23 x 10^4 seconds to reach its destination. Ab
vagabundo [1.1K]

Multiply the two values together. 7.62 x 1.23 = 9.3726
10^2 x 10^4 = 10^6.

9.3726 x 10^6 is the answer in Scientific Notation.

6 0
3 years ago
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