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3 years ago

Which graph shows a proportional relationship between x and y?

Mathematics

2 answers:

kogti [31]3 years ago

7 0

Answer:

I can't answer without picture

Step-by-step explanation:

sp2606 [1]3 years ago

4 0

Answer:

B i think i need see a image tho

Step-by-step explanation:

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Sam is practicing long track speed skating at an ice skating rink The distance around the rink and 250 yards has skated around t

Vladimir [108]

There are 1760 yards in one mile and the rink is 250 yard in perimeter.

This means 3 miles is 5280 yards.

If Sam has already gone around the whole rink 6 times, that means he was traveled a total of 1500 yards.

Sam has 3780 more yards to travel 3 miles.

This means he needs to do 15.12 more laps around the rink. Or 16 if you are rounding.

Hope this helps! :)

3 0

2 years ago

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THE amusement park won't allow kids to ride roller-coasters until they are a minimum of 48 inches tall. Michael is now 42 inches

saveliy_v [14]

Answer: It will one year (or 12 months) before Michael is able to ride the roller coaster.

Step-by-step explanation: Because he grows a half inch every month, this means that It takes him two months to grow one full inch. Because he has to grow six inches, you just multiply 2 by 6 to get 12 months or one year.

7 0

2 years ago

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Could the inverse of a non-function be a function? Explain or give an example.

Kitty [74]

Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form $(a,\, b)$ . The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.

A mapping is a function if and only if for each possible input value $x$ , at most one of the distinct pairs includes $x\!$ as the value of first entry.

For example, the mapping $\lbrace (0,\, 0),\, (1,\, 0) \rbrace$ is a function. However, the mapping $\lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace$ isn't a function since more than one of the distinct pairs in this mapping include $1$ as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping $\lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace$ is the mapping $\lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace$ .

Consider mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ . This mapping isn't a function since the input value $0$ is the first entry of more than one of the pairs.

Invert $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ as follows:

$(0,\, 0)$ becomes $(0,\, 0)$ .
$(0,\, 1)$ becomes $(1,\, 0)$ .
$(1,\, 0)$ becomes $(0,\, 1)$ .
$(1,\, 1)$ becomes $(1,\, 1)$ .

In other words, the inverse of the mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ would be $\lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!$ , which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function $\mathbb{R} \to \mathbb{R}$ mappings, including circles) are also non-function mappings.