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Anit [1.1K]
4 years ago
14

I NEED THIS DONE HELP

Mathematics
1 answer:
eimsori [14]4 years ago
4 0

Answer:

A) f = e x 15

Step-by-step explanation:

Whenever you multiply the e input value by fifteen, you get the correlation d output value.

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What do the equations have in common? y = -2 x + -3 y = -2 x + -3
nalin [4]

Answer:- the equation have -2x common.

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Can someone help me please
schepotkina [342]

Answer:

∠B=60°

Step-by-step explanation:

In this right traingle, using angle B, you have the opposite side which is 6√102, and the adjacent side which is 6√34. Using SOHCAHTOA this invlolves TOA so tangent B = OPPOSITE/ADJACENT or tan B = 6√102/6√34. Simplifying gives tan B=√3. You can use your calculator to solve for B by taking the inverse tangent of √3 or you can use the known trig ratios from the unit circle if you have already learned that to find that  angle B is 60°

5 0
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Find the line integral of f(x, y) = y e^X^2 along the curve r(t) = 3t i - 4t J, -2 lessthanorequalto t lessthanorequalto -1. The
Semenov [28]

\vec r(t)=3t\,\vec\imath-4t\,\vec\jmath

\implies\left\|\dfrac{\mathrm d\vec r(t)}{\mathrm dt}\right\|=\|3\,\vec\imath-4\,\vec\jmath\|=\sqrt{3^2+(-4)^2}=5

The line integral of f(x,y) along the curve C parameterized by \vec r(t) is

\displaystyle\int_Cf(x,y)\,\mathrm ds=\int_{-2}^{-1}f(3t,-4t)\left\|\dfrac{\mathrm d\vec r(t)}{\mathrm dt}\right\|\,\mathrm dt=-20\int_{-2}^{-1}te^{9t^2}\,\mathrm dt

Substitute u=9t^2 so that \mathrm du=18t\,\mathrm dt. Then

\displaystyle\int_Cf(x,y)\,\mathrm dS=-\frac{20}{18}\int_{36}^9e^u\,\mathrm du=\frac{10}9\int_9^{36}e^u\,\mathrm du=\boxed{\frac{10}9(e^{36}-e^9)}

8 0
4 years ago
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Afina-wow [57]
The value of y can be calculated by translating the equation such that we solve y in terms of x.

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Then, we substitute 2 to the x in the equation.

                             y = (10 + 3(2)) / - 8  = 16/-8

                                y = -2 

Thus, the value of y in the equation is -2. 
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Just count the boxes and you should get the answer
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