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Tema [17]
3 years ago
7

How to find the difference

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0
Find a common denominator. for example the third question is 2/3-2/5. the common denominator would be 15 because both are divisible by 15. since you multiply three, 5 times to get 15 you multiply 2 by 5 which is ten (new fraction is 10/15). then the other is 2/5 so same thing with the other one it takes three fives to get to 15 so its 2 times 3 which is six (new fraction is 6/15) you have to qual out each side. 10/15-6/15 is 4/15
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The sum of five and twice a number is 33
Alex777 [14]

Answer:

it is 5

Step-by-step explanation:

because 25 time 33 is 54 and that why it is 5

6 0
3 years ago
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-) LaTanya is decorating her living room and draws
Alona [7]

Step-by-step explanation:

First she need to measure the complete wall distance and then divide it by 2

(I just tried the answer, Sorry if it is wrong)

We need not go so depth in this question and find it logically.

5 0
3 years ago
Driving under the influence of alcohol (DUI) is a serious offense. The following data give the ages of a random sample of 50 dri
o-na [289]

Answer:

Explanation below.

Step-by-step explanation:

For this case we have the following dataset:

46, 16, 41, 26, 22 ,33, 30, 22 ,36, 34,

63, 21, 26, 18, 27, 24, 31, 38, 26, 55,

31,  47, 27, 43 ,35, 22 ,64,40, 58, 20,

49, 37, 53, 25, 29, 32, 23, 49, 39, 40,

24, 56, 30, 51, 21, 45, 27, 34, 47, 35

So we have 50 values. The first step on this case would be order the dataset on increasing way and we got:

16, 18, 20, 21, 21, 22, 22, 22, 23, 24,

24, 25, 26, 26, 26, 27, 27, 27, 29, 30

30, 31, 31, 32, 33, 34, 34, 35, 35, 36,

37, 38, 39, 40, 40, 41, 43, 45, 46, 47,

47, 49, 49, 51, 53, 55, 56, 58, 63, 64

We can find the range for this dataset like this:

Range = Max-Min = 64-16 =48

Then since we need 7 classes we can find the length for each class doing this:

W = \frac{48}{7}=6.86

And now we can define the classes like this and counting how many observations lies on each interval we got the frequency:

  Class           Frequency      Midpoint           RF                   CF

________________________________________________

[16-22.86)              8               19.43         (8/50)=0.16           0.16

[22.86-29.71)         11              26.29        (11/50)=0.22          0.38

[29.71-36.57)         11               33.14         (11/50)=0.22          0.6

[36.57-43.43)         7               40.0          (7/50)=0.14           0.74

[43.43-50.29)        6               46.86        (6/50)=0.12          0.86

[50.29-57.14)         4               53.72        (4/50)=0.08         0.94

[57.14-64]               3               60.57        (3/50)=0.06           1.0

________________________________________________

Total                         50                                         1.00

RF= Relative frequency. CF= Cumulative frequency

The relative frequency was calculated as the individual frequency for a class divided by the total of observations (50)

The mid point is the average between the limits of the class.

And the cumulative frequency is calculated adding the relative frequencies for each class.

8 0
4 years ago
What is Integers? Can you explain it?
nexus9112 [7]

Answer: integers are: -5, 1, 5, 8, 97, and 3,043

Step-by-step explanation: any number such as negatives and positive, as long as its a whole number.

3 0
2 years ago
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HELP! please explain how to solve the point of maximum growth rate for the logistic function?!?? I'm really confused!
lora16 [44]

Answer:

18 units over 210 units of time

Step-by-step explanation:

the function reaches its limit at 116 and starts at 0 at -94

|-94|+|116|=210

8 0
3 years ago
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