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RSB [31]
3 years ago
12

There are 7 bags. 2 bags are big. The rest are small.How many bags are small?

Mathematics
1 answer:
siniylev [52]3 years ago
6 0
7-2=5
Ans: 5 bags are small.
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Beth has already jogged 3 miles. She plans to jog less than 12 miles. Which inequality can be
8090 [49]

Answer:

x + 3 < 12

Hope this helps :)

8 0
3 years ago
Suppose that f(x)=x2 and g(x) =4/5x2. Which statement best compares the graph of f(x)?
Roman55 [17]

Answer:

See below.

Step-by-step explanation:

Are f(x)=x2 and g(x) =4/5x2 correctly written?

This answer assumes they are supposed to be:

f(x)=x^2 and g(x) = (4/5)x^2

If these revisions are correct, g(x) would produce values that are (4/5) of f(x).

See attached graph.

I don't see any of the options for "best statement."

6 0
2 years ago
rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t
ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

y=h+ut+\frac{1}{2}at^2

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

a=g=-9.8 m/s^2 is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

11=23+27t-4.9t^2\\4.9t^2-27t-12=0

This is a second-order equation, which has solutions:

t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}

So

t_1 = -0.41 s

t_2=5.92 s

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0
3 years ago
Pls help i really really need help on this. We just learned this but i can't remember it.
bulgar [2K]

Answer:

114 cm²

Step-by-step explanation:

Area of shaded region

= area of circle -area of square

\boxed{area \: of \: circle = \pi {r}^{2} }

Given that radius= 10cm, r= 10cm.

\boxed{area \: of \: square = side \:  \times side}

Let the length of a side of the square be x cm.

Applying Pythagoras Theorem,

10² +10²= x²

100 +100= x²

x²= 200

x =   \sqrt{200}

Area of square

= x²

= 200cm²

Area of shaded region

= 3.14(10²) -200

= 3.14(100) -200

= 314 -200

= 114 cm²

8 0
2 years ago
1/5x-2/3y=30 when y=15
dolphi86 [110]

Answer:

Step-by-step explanation:

<u>Step 1:  Set y to 15 and solve</u>

<u />\frac{1}{5}x - \frac{2}{3}*15=30

\frac{1}{5}x-10=30

<em>Add 10 to both sides</em>

<em />\frac{1}{5}x-10+10=30+10

\frac{1}{5}x=40

<em>Multiply both sides by 5</em>

<em />\frac{1}{5}x*\frac{5}{1}=40*\frac{5}{1}

x=200

Answer:  x=200

5 0
2 years ago
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