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kirill115 [55]
3 years ago
7

Which of the following is not a rational number?A)22 B) ⅓ C)―16 D) 0.343

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0
Its 0.343 because it cannot be expressed as a fraction or whole number
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If x is the least common multiple of the set {6, 8, 12} and y is the greatest common factor
Anarel [89]

Answer:

12

Step-by-step explanation:

The least common multiple of {6,8,12} is 24. This can be intuitively figured by noting that any multiple of 12 is a multiple of 6 and that 12 is 1.5x larger than 8. That means we only have so multiple 12 by 2 and 8 by 3 for them to be equal. The GCF of {20,42,72} is 2 as the prime factorization of 20 is 2x2x5 and 42 is 2x3x7. That means even without having to check 72 (which is clearly even so 2 is a factor), we know that 2 is the greatest common factor that they could share. So X/Y = 24/2 = 12

8 0
2 years ago
You are in a bike race. When you get to the first checkpoint, you are $\frac{2}{5}$
Black_prince [1.1K]

Answer:

The distance from the star to the second checkpoint is 4 miles

Step-by-step explanation:

The complete question in the attached figure

we know that

When you get to the second checkpoint, you are 1/4 of the distance to the finish

so

The distance from the star to the second checkpoint is equal to the total distance multiplied by 1/4

The total distance is 40 miles ( see the attached figure)

so

The distance from the star to the second checkpoint is

\frac{1}{4}(40)=10\ miles

<em>Find out the distance from the start to the first checkpoint</em>

Multiply the distance from the star to the second checkpoint by 2/5

\frac{2}{5}(10)=4\ miles

6 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
If the date of the second Thursday of the month is a perfect square, what is the date of the last Monday of the month?
Inga [223]

Answer:

last Monday is 27

Step-by-step explanation:

perfect square: 4, 9 , 16

2nd Thursday is a day >5 and < 14 day from the begining of the month, therefore the only day fit the criteria is 9th of the month.

last Monday is 27

Sun Mon Tue Wen Thu Fri Sat

                                  9     10  11

12    13      14     15     16     17  18

.........................................................

26    27

3 0
3 years ago
A student scores 83, 90, and 85 on the first three science tests of the year in order to have a test average of at least 87, the
Evgesh-ka [11]
Hope you find this helpful!

5 0
3 years ago
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