1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlekseyPX
3 years ago
14

PLEASE HELP URGENT!!!!!! WILL GIVE BRAINLIEST!!!! MATH!!!!

Mathematics
2 answers:
max2010maxim [7]3 years ago
4 0
What’s your question?
Arisa [49]3 years ago
3 0

Answer:

ok

Step-by-step explanation:

You might be interested in
PLEASE HELP!! What is the domain of (f)
pishuonlain [190]

The domain is (-5,4). If that makes any sense, if it doesnt ill explain


4 0
3 years ago
Algebra II Help??? Subtracting Fractions<br><br> (2x)/(y^2-x^2) - (x)/(y-x)
denis23 [38]
Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}=
\frac{2x-x(x+y)}{y^2-x^2}=
\frac{2x-x^2-xy}{y^2-x^2}
4 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
Find the value of the expression 12 ÷ v for v = 2
Zarrin [17]

Answer:

Step-by-step explanation:

12 / v....when v = 2

12 / 2 = 6 <==

3 0
3 years ago
Read 2 more answers
Determine if A^-1 C=C A^-1 Given:<br><br> A^-1 C=
ryzh [129]

<em>CA </em>⁻¹ is undefined because there are more columns in <em>A </em>⁻¹ than there are rows in <em>C</em>.

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is the length of side x? (possibly use similar triangles)
    14·1 answer
  • what statement is false. A. Every rational number is also real B. Every real number is also rational C. Every integer is also a
    8·1 answer
  • A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researchers accepts
    15·1 answer
  • Given point A (3, 8) and point B (-5, 1). Find the following: a.) The coordinates of the midpoint of segment AB. Write your answ
    9·1 answer
  • A walking path across a park is represented by the equation y = -4x+10. A
    7·1 answer
  • Help me pleaseee !!
    13·1 answer
  • PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
    5·2 answers
  • Given that these triangles are similar, which side corresponds to side GE?
    10·2 answers
  • Please answer the question in the image
    15·1 answer
  • PLZ HELP ME ITS DUE TOMORROW!!!!
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!