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3 years ago

Write down the general zeroth order linear ordinary differential equation. Write down the general solution.

1 answer:

7 0

The zeroth derivative of a function $y(x)$ is simply the function itself, so the zeroth order linear ODE takes the general form

$y(x)=f(x)$

whose solution is $f(x)$ .

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You have just used the network planning model and found the critical path length is 30 days and the variance of the critical pat

joja [24]

Answer:

0.726 is the probability that the project will be completed in 33 days or less.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30 days

Variance = 25 days

Standard Deviation,

$\sigma = \sqrt{\text{Variance}} = \sqrt{25} = 5$

We assume that the distribution of path length is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(completed in 33 days or less)

$P( x \leq 33) = P( z \leq \displaystyle\frac{33 - 30}{5}) = P(z \leq 0.6)$

Calculation the value from standard normal z table, we have,

$P(x \leq 33) = 0.726 = 72.6\%$

0.726 is the probability that the project will be completed in 33 days or less.

8 0

3 years ago

Find the product 1/2x3/4.

Sauron [17]

Answer:

The product is 3/8

Step-by-step explanation:

When you multiply two fractions, first multiply the numbers on the top (numerators).

1 * 3 = 3

Then multiply the bottom numbers (denominators).

2 * 4 = 8

Now stick the first over the second.

3/8

7 0

3 years ago

Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m <br> a. 17.32 m<br> b. 6.93 m<b

zepelin [54]

In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m

7 0

3 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

3 years ago

Please help 40 points

Natasha2012 [34]

Answer:

-2 5/9

Step-by-step explanation:

w + (-x) - 2/3

Let w = -5/9 and x = 4/3

-5/9 - 4/3 - 2/3

Get a common denominator

-5/9 -4/3*3/3 -2/3*3/3

-5/9 -12/9 -6/9

Add

-23/9

Change to a mixed number

-2 5/9

4 0

3 years ago