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blagie [28]
3 years ago
14

When graphed, which parabola opens downward? y = –3x2     y = (x – 3)2    y = x2 – 3   

Mathematics
2 answers:
Elan Coil [88]3 years ago
7 0

we know that

the equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2} +k

where

(h,k)-------> is the vertex of the parabola

if a > 0 -------> the parabola open upwards

if a < 0 -------> the parabola open downwards

<u>case A)</u> y=-3x^{2}

a =-3

so

a < 0 -------> the parabola open downwards

the vertex is the point (0,0) ------> is a maximum

therefore

y=-3x^{2} open downwards

<u>case B</u>) y=(x-3)^{2}

a =1

so

a > 0 -------> the parabola open upwards

the vertex is the point (3,0) --------> is a minimum

therefore

y=(x-3)^{2} open upwards

<u>case C</u>) y=x^{2}-3

a =1

so

a > 0 -------> the parabola open upwards

the vertex is the point (0,-3) --------> is a minimum

therefore

y=x^{2}-3 open upwards

therefore

<u>the answer is</u>

y=-3x^{2} open downwards

In-s [12.5K]3 years ago
6 0

The answer to this question is y = –3x^2, just had this on e2020 :)

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