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3 years ago

Find the median and mean for each data set.

Mathematics

2 answers:

Bas_tet [7]3 years ago

8 0

Answer:

1. med.=6, mean=5.625

Step-by-step explanation:

this is for the first row

ch4aika [34]3 years ago

8 0

Answer:

top mean 5.625‬ top median 6

bottom mean 5.75‬ bottom median 5.5

Step-by-step explanation:

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Find angle B. What is angle B.

julsineya [31]

Answer:

B=45 Degrees

Step-by-step explanation:

You can use law of sines to answer. Law of Sines states that $\frac{sin(a)}{A} =\frac{sin(b)}{B}$ . That means that $\frac{sin(60)}{4\sqrt{6} }=\frac{sin(b)}{8}$ . Multiplying 8 to both sides gives us $\frac{8sin(60)}{4\sqrt{6} }=sin(b)$ . By using inverse of sin, we get $b = sin^{-1} (\frac{8sin(60)}{4\sqrt{6} } )$ . Plugging that into a calculator gives us b=45 degrees.

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3 years ago

I need to know what the equation is for this graph..

Lostsunrise [7]

Answer:

The choice second

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2 years ago

What is the answer to this question above?

djyliett [7]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A driver who drives at a speed of r mph for t hr will travel a distance d mi given by dequalsrt mi. How far will a driver travel

liubo4ka [24]

Answer:

At a speed of 57 mph for 8 hr a driver will travel 456 mi

Step-by-step explanation:

Here we have a summary of the letters for each variable:

Speed ---> r (in units of mph)

Time ---> t (in units of hr)

Distance ---> d (in units of mi)

These three variables are related by the next formula:

d = rt

In the data they give to you: 57 mph and 8 hr, they are telling you the r and the t, respectively:

r = 57 mph

t = 8 hr

The only thing you have to do is replace the values:

d = rt ----> d = 57 mph x 8 hr

d = 456 mi

5 0

4 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

4 years ago