Write the function in standard form. Y=(3x-2)(3x+6)
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The equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0) is
We have to find the equation of a parabola that opens up and has the following x intercepts (-3, 0) and (4, 0)
x-intercepts of the parabola are (−3, 0) and (4, 0)
So, we can form an equation:
Also x = 4
x – 4 = 0
x – 4 = 0 is another factor of quadratic equation.
The quadratic function is:
Hence, the equation of the parabola is