Distances in 2- and 3-dimensions (and even higher dimensions) can be found using the Pythagorean theorem. The straight-line distance can be considered to be the hypotenuse of a right triangle whose sides are the horizontal and vertical differences between the coordinates.
Here, you have A = (0, 0) and B = (3, 6). The horizontal distance between the points is ...
... 3 - 0 = 3 . . . . the difference of x-coordinates
The vertical distance between the points is ...
... 6 - 0 = 6 . . . . the difference of y-coordinates
Then the straight-line distance (d) between the points is found from the Pythagorean theorem, which tells you ...
... d² = 3² + 6²
... d = √(9 + 36) = √45 ≈ 6.7 . . . units
Answer:
The answer is D. (x-4)^2
Step-by-step explanation:
It has a horizontal shift of 4 to the right
Answer:
12.3 feet.
Step-by-step explanation:
As we are given that
is an right angled triangle.

And we have to find out the value of side OP to the nearest tenth of a foot by rounding off the value as seen in the attached figure as well.
By using Trigonometric functions in a right angled
, we know that:

Here,
is
, Perpendicular is side <em>OP</em> and Base is side <em>PN</em>.
So, 

Putting the values of <em>PN </em>and
.

Hence, the value of <em>OP </em>is
.
Tenth place is the answer!! :))