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andreyandreev [35.5K]
3 years ago
11

Cual es el número de una deuda de $80.000​

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

se paga 36,000

Step-by-step explanation:

espero te ayude

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In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.
slava [35]

Answer:

49

Step-by-step explanation:

∆ABC~ ∆XYZ

AB= 11 that is half of XY = 22

therefore XZ/2 = AC (base) = 32/2 = 16

and YZ /2 = BC(hypotenuse) = 44/2 = 22

(a= 11, b= 16, c= 22)

perimeter of a triangle

P = a+b+c

P= 11+16+22= 49

8 0
3 years ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
Write 0.414141414141 as a fraction?
igor_vitrenko [27]

Answer:

The fraction is 41/99.

Step-by-step explanation:

The steps are :

let \: x \: be \: fraction,

x = 0.414141.....

100x = 41.414141.....

100x - x = 41.414141.....  \:  -  \: 0.414141.....

99x = 41

x =  \frac{41}{99}

4 0
3 years ago
Please help! this is timed!
Scilla [17]

Answer: -8-10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
the length of a rectangle is 2 inches less than twice its width. If the perimeter of the rectangle is 74 inches, what is the are
schepotkina [342]
If the width is w and the length is l, then 2w-2=l and 2w+2l=72 (using the perimeter equation). Plugging 2w-2 in for l, we get 2w+(2w-2)*2=72 and 6w-4=72. Adding 4 to both sides, we get 6w=76. After that, we divide both sides by 6 to get 74/6=w. Since l=2w-2=136/6, we get (136/6)(74/6)=656.75=area
5 0
3 years ago
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