Food-grade lubricants must perform the same technical functions as any other lubricant: provide protection against wear, friction, corrosion and oxidation, dissipate heat and transfer power, be compatible with rubber and other sealing materials, as well as provide a sealing effect in some cases.
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Answer:
-45, 1, 4, 5, 9
Explanation:
The first argument value, -5, is less than -1, so the first section of the function definition is used. f(-5) = 9(-5) = -45.
The 2nd to 5th argument values are in the interval [-1, 3], so the second section of the function definition is used.
The last argument value, 6, is greater than 3, so the last section of the function definition is used. f(6) = (6 -3)^2 = 9.
Function values are shown in the table attached.
Answer:
D is the correct answer , if im wrong sorry. hope it helps
Explanation:
it was right for me on my test
Considering the data in the question, the focal length of the objective lens that will give a total magnification of 200x is <u>0.8cm focal length.</u>
The whole question is:
You are using a microscope with a 10x eyepiece. What focal length of the objective lens will give a total magnification of 200x? Assume a length L = 160mm.
<h3>How was the answer derived?</h3>
Given that total magnification is 200
And the Assume length is 160
Since we used a microscope with a 10x eyepiece, the magnification would be divided by 10.
=> 200 ÷ 10 = 20.
Also, the focal length is measured in centimeters or meters; we would change the millimeters of focal length to centimeters. Therefore, we have 160 ÷ 10 = 16
The formula for the focal length of the objective lens = assumed length ÷ total magnification.
=> 16 ÷ 20 = 0.8cm.
Hence, in this case, it is concluded that the correct answer is "0.8cm."
Learn more about the focal length of the objective lens here: brainly.com/question/15744335
