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3 years ago

having a blonde moment here lol. harvey is 3 times as old as jane. the sum of their ages is 48. find the age of each

Mathematics

2 answers:

GarryVolchara [31]3 years ago

8 0

Answer: could be wrong but I believe that their age is 24. Hope it helps

Step-by-step explanation:

AURORKA [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Jane = x = 12yrs

Harvey = 3x = 36yrs

3x + x = 48

4x = 48

x = 12

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Question 2

Stella [2.4K]

Answer:

12x + 20

Step-by-step explanation:

2(4x + 6 +2x + 4)

5 0

2 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago

Any help plzzz I’ll appreciate it so much thank u

docker41 [41]

9514 1404 393

Answer:

5√5

Step-by-step explanation:

Use the distance formula:

d = √((x2 -x1)² +(y2 -y1)²)

d = √((-7-(-2))² +(-7-3)²) = √((-5)² +(-10)²) = √(25 +100)

d = √125 = √(25·5)