The distance between the points is 5
Answer:

Step-by-step explanation:
Write down the problem;

Simplify

Convert so that the fractions have a common denominator; multiply the numerator and denominator of both fractions such that the denominators are equal;

Add the fractions;

Convert to mixed number;

A has fixed one time fee of $12 and if you go to it say "m" months you pay $28 for each month, so your total cost at A is really 12 + 28m.
B has a fixed one time fee of $20 and if you go to it "m" months you pay $26 for each month, so you total cost at B is 20 + 26m.
how many months for the cost to be the same?

well, since the cost for both is the same, we can just get A's, knowing that B is the same

Answer:
Step-by-step explanation:
It’s nothing
Answer: B
Step-by-step explanation:
A proper fraction is when a fraction has the numeration less than the denominator