Answer:
Rise over Run, the slope in this graph would be 3/4
Step-by-step explanation:
You count the number of spaces it takes to move up, then you move right, towards the line. You write the rise number on top and the number moving right (run) on the bottom, (rise over run).
I hope this helps you, if not let me know in the comments :)
Answer:
7/20
Step-by-step explanation:
given,
2r = 7/10
r= 7/10*1/2
r= 7/20
So use undistributive properyt]
ab+ac=a(b+c)
so factor 24a dadn 28 to find 'a' the common factor
24=2 times 2 times 2 times 3 tiems a
28=2 times 2 times 7
common one is 2 itmes 2=4
a=4
4(2 times3 times a)+4(7)=4(6a)+4(7)=4(6a+7)
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
