<span>We need to calculate noon sun angle. Noon sun angle is an angle at which sun-rays fall at noon on a given date.
</span>On September 22, the sun’s rays form a 90° angle at noon at the equator.
Formula for calculating noon sun angle is:
Noon_sun_angle = 90° - Zenith angle
We have complementary angles so we need to substract zenith angle from 90°.
The zenith angle is the distance between subsolar point (point where sun is at 90°) and the latitude of an observer. In our case this angle will have same value as latitude because subsolar point is at equator 0°. If our latitude and subsolar point are at same hemisphere we substract values. Otherwise we add values.
New Orleans, USA
Latitude = 30°
Noon_sun_angle = 90° - 30° = 60°
Helsinki, Finland
Latitude = 60°
Noon_sun_angle = 90° - 60° = 30°
C=2πr
Hoped i helped BYEEEEEEEEEEEEEEEEEEEEEEEEE
Given the similar triangles, it can always be noted that similarity can be derived from the proportionality of the leg lengths, however it is not true the the ratio of the proportion of the leg lengths is equal to the slope of the triangles. Thus the false statement is:
A] <span>The slope of the hypotenuse is represented by the ratio of the leg lengths.</span>
Answer:
The p-value for two-tailed test is 0.136
Step-by-step explanation:
Given;
one-tail test, p-value = 0.068,
In one-tailed test, we test for the possibility of a relationship in one direction and completely disregard the possibility of a relationship in the other direction.
One-tail test provides possibility of an outcome in one direction, while
two-tail test provides possibility of an outcome in two different directions.
Thus, the p-value for two-tailed test = 2 x 0.068 = 0.136
Answer:
Step-by-step explanation:
The Universal Set, n(U)=2092
Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects,
