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3 years ago

I need help with this questions.

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

#10 ) 6/x = 5/11 OR 6/x = 9/19.8

5x = 66 9x = 118.8

x = 13.2 x = 13.2

#11 ) original photo is 5 inches by 7 inches, multiply that , = 35 ( area of original photo )

new photo is "3 times larger" so 5 become 15 and 7 become 21 , multiply that which gives you 315 (area of enlarged photo )

take the enlarged photo's area divided by the original photo's area which gives you 9

#12 ) 6/8 = x/12

72 = 8x

9 = x

#13 ) set equal to find segment TR : 4/10 = 6/x

4x = 60

x = 15

then find the perimeter of triangle by P = a + b + c

P = 10 + 12 + 15

P = 37

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The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0

Change in weight per day of hibernation = - 0.03
Change in weight for 115 days = - 3.45 ounces

A linear model can be created using the data in the table given using a regression calculator or excel ;

The linear model obtained in the form y = m + bx is :

y = - 0.03x + 0
y = change in weight
x = number of days of hibernation
Intercept = 0
Slope = -0.03

The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.

Using the regression equation, substitute, the vlaue of x = 115
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Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.

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1 year ago

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3 years ago

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Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

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Answer:

Explanation:

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2 years ago

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Nuetrik [128]

Answer:

Step-by-step explanation:

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3 years ago

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