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zhuklara [117]
4 years ago
12

I need some help please ​

Mathematics
1 answer:
Sedaia [141]4 years ago
8 0
It’s B, 32/4= 8 and 4/4 = 1
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A pump can move 42 gallons of water in 7 minutes. Find the unit rate
Crazy boy [7]
In 1 min the thing can pump 6 gallons of water
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3 years ago
Need help on this ???????????
GREYUIT [131]

Answer:

First choice

-∞ < y< ∞

Step-by-step explanation:

In this function,we need to use graph in order to find out the range.

Graph is attached.

  • \boxed{ -  \infty  < y <  \infty }

6 0
3 years ago
Help for both a and b
kipiarov [429]

Hi!

Remember that an x-intercept is a point in which the line touches the x-axis (the horizontal line). And, the y-intercept is a point in which the line touches the y-axis (the vertical/up and down line)

-----------------

For A)

The coordinate of the y-intercept is (0,1)

The coordinate of the x-intercept is (3,0)

For B)

The coordinate of the y-intercept is (0,0)

The coordinate of the x-intercept is (0,0) !

*both the x and y axis meet at the origin. So, a line that goes through the origin (0,0) is intersecting with BOTH the x and y-axis.

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5 0
3 years ago
What is the product of (-6)(-7)(-1)?<br> оооо
Yanka [14]

Answer:

-42

Explanation:

(-6)(-7)(-1)

do (-6)(-7)

-negative sign and -negative sign= +positive sign

(-6)(-7)=42

(42)(-1)

+positive sign and -negative sign=-negative sign

answer:

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3 0
3 years ago
Read 2 more answers
PLEASE SHOW WORK
CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

V = \dfrac{\pi}{3}r^2h

Taking the derivative of V with respect to time, we get

\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)

\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)

Since r is always equal to h, we can set

\dfrac{dr}{dt} = \dfrac{dh}{dt}

so that our expression for dV/dt becomes

\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)

\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}

Solving for dh/dt, we get

\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}

\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})

\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}

7 0
3 years ago
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