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P(at least 2 students have the same birthday)= 1- P(no 2 students have the same birthday)
Because P(A)=1-P(A'), where A is an event, and A' the complement of that event.
P(no 2 students have the same birthday)=
think of the problem as follows. We have an urn of balls, numbered from 1 to 365 (the number of the days of the year.
What is the probability of picking 56 different numbered balls, with replacements?
The first one can be any of the 365
the second any of 364 (since one selection has already been made)
the third any of the 363
.
.
and so on
the 56th selection is one of 310 left
Answer:
Answer:
Look below
Step-by-step explanation:
Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.
This means triangle BCD is a 30-60-90 (angle measures) right triangle
The proportions of the sides (from smallest to largest) is
x:x√3:2x
We are given that BC = 6 cm. This means...
2x=6
x=3
This means DB is 3 cm and CD is 3√3 cm
Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.
x=3√3
x√3=9
2x=6√3
Now we need to find AB
AB = AD + DB
AB = 9 + 3
AB = 12 cm