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julsineya [31]
3 years ago
10

What is the greatest common factor "GCF" of 24x^2 y^3 z^4 + 18x^6 z - 36x^3 y^2

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

6x^2

Step-by-step explanation:

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Can someone explain this question?I know the answer is t=0 but don't know why:(
Dafna1 [17]

Answer:


Step-by-step explanation:

Your axis of symmetry is always going to be related to the x-point of your vertex. In this case, it looks like the vertex of the parabola is (0, 9). The vertex is the highest (or lowest) point of the parabola and is even on both sides. This means that, in order to be symmetrical, you would need to divide this parabola down "0."

5 0
2 years ago
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Elyssa works as an assistant coach. She earns $10.95 per hour. How much will she get
saul85 [17]

Answer:

82.125

≈82.12 ( am not sure if it need to be estimated )

Step-by-step explanation:

1 hr -> 10.95

30m-> 5.475

10.95x7=76.65

76.65+5.475=82.125

                    ≈82.12 ( am not sure if it need to be estimated )

7 0
3 years ago
In the box, type the number that correctly completes the sentence.
VLD [36.1K]
He would receive $5.63, not including tax
6 0
3 years ago
Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelo
Digiron [165]

Answer: (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

Step-by-step explanation:

Transformation rule for dilation:

(x,y)\to(kx,ky) , where k = scale factor

Given : Scale factor = -\dfrac13

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)

(0,9)\times(0\times-\dfrac13,9\times-\dfrac13)=(0,-3)

(6,-3)\to(6\times-\dfrac13,\ -3\times-\dfrac13)=(-2,1)

(3,-3)\to (3\times-\dfrac13,\ -3\times-\dfrac13)=(-1,1)

Hence, the coordinates of the image if the parallelogram = (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

8 0
2 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5 percent of these are defective.

This means that p = 0.05

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.0025 = 0.25% probability that both are defective

4 0
2 years ago
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