9. D because it fits the description when it is graphed.
11. D because it has the correct vertex, which is (1.5, 4.75).
12. f(x)=-4(x-2)²+16 works with the table and provided graph!
13. 0 isn't a zero for f(x), so B is correct (the zeros are 1/2 and 4).
14. The width is about 3.831.
15. The answer is B because the equation for a parabola in this form is:
f(x) = (x - r₁)(x - r₂)

Every one of these except for 15 was solved using desmos, a graphing calculator.

Hope this helps!

7 0

3 years ago

Convert the rate 1000 ounces per 2 hours to cups per minutes?

Andrews [41]

125 cups in 120 minutes (because 1000 oz/8 = 125 cups and 2 hrs is 120 minutes)

$\frac{125}{120} = \frac{n}{1}$

now reduce the fraction by dividing the numerator and denominator by 5 = (optional)
$\frac{25}{24} = \frac{n}{1}$
So 24n = 25 Divide both sides by 24
n= 1 1/24 cups per minute

5 0

3 years ago

1. A gambler makes 100 column bets at roulette. The chance of winning on any one play is 12/38. The gambler can either win $ 5 o

lapo4ka [179]

Answer:

a) Expected amount of the gambler's win = $0.209

b) SD = 2.26

c)P (X >1) = P(z >0.35) = 0.36317

Step-by-step explanation:

The probability of winning, p = 12/38 =6/19

Probability of losing, q = 1 -p = 1-6/19

q = 13/19

Win amount = $5

Loss amount = $2

a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)

Expected total amount of win = 1.579 - 1.369

Expected amount of win, E(X) = $0.209

b) Standard Deviation for the total amount of the gambler's win

$SD = \sqrt{E(X^{2}) - (E(X))^{2} }$

E(X²) = (6/19)*5² - (13/19)*2²

E(X²) = 5.158

$SD = \sqrt{5.158 - 0.209^2}$

SD = 2.26

c) probability that, in total, the gambler wins at least $1.

P(X >1)

$z = \frac{X - \mu}{\sigma}$

μ = E(x) = 0.209

z = (1-0.209)/2.26

z = 0.35

P( X >1) = P(z >0.35)

P(z >0.35) = 1 - P(z <0.35)

P(z >0.35) = 1 - 0.63683

P(z >0.35) = 0.36317

5 0

3 years ago