These two rectangles are similar. Which is a correct proportion for corresponding sides?

Mathematics

2 answers:

Keith_Richards [23]3 years ago

7 0

Answer:

option (2) is correct.

$\frac{4}{8}=\frac{12}{x}$

Step-by-step explanation:

Given two similar rectangles and with dimension of sides,

we have to choose the correct proportion for corresponding sides.

Since, the rectangles given are similar rectangles.

So, the corresponding sides are in same proportion in case of similar figures,

So,

$\frac{4}{8}=\frac{12}{x}$

Thus, option (2) is correct.

bagirrra123 [75]3 years ago

5 0

Answer:

$\frac {12} {x} = \frac {4} {8}$

Step-by-step explanation:

We are given two similar rectangles with their side lengths.

We are to figure out whether which of the given options is the correct proportion for corresponding sides.

Since the rectangles are similar, so the corresponding sides will be on the same side.

Therefore, the correct answer option is $\frac {12} {x} = \frac {4} {8}$ .

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Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$