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tankabanditka [31]
3 years ago
8

Use the function below to find F(3). F(x) = (1/4)^x

Mathematics
2 answers:
Amanda [17]3 years ago
5 0

Answer:

Step-by-step explanation:

F(x) = (1/4)^x    F(3)

F(3) = (1/4)^3

F(3) = (1/4)×(1/4)×(1/4)

F(3) = 1/64

riadik2000 [5.3K]3 years ago
4 0

Answer:

The answer is 0.015625

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On the last day of the school book fair, all pencils were one set price and all books were a different set price. Sammy bought 2
Lady bird [3.3K]

Answer:

  • Book -$20/11 and pencil - $17/11

Step-by-step explanation:

Let the set price of pencil be p and the set price of book be b

<u>Then we have equations:</u>

  • 2p + 6b = 14
  • 4p + 1b = 8

<u>Simplify the first equation:</u>

  • p + 3b = 7

<u>And substitute p in the second equation: p = 7 - 3b</u>

  • 4(7 - 3b) + b = 8
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<u>And finding value of p:</u>

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3 years ago
An oil slick is expanding as a circle. The radius of the circle is initially 2 meters and increases at the rate of 21 meters per
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Step-by-step explanation:

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3 years ago
Which of this ones is an example of a probability?
Sidana [21]

Answer:

The answer is C

Step-by-step explanation:

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8 0
3 years ago
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Multiple-Choice Integration, Picture Included, Please Include Work
ValentinkaMS [17]
\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx

Recall that a circle of radius 2 centered at the origin has equation

x^2+y^2=4\implies y=\pm\sqrt{4-x^2}

where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius r is \pi r^2, it follows that the area of a quarter-circle would be \dfrac{\pi r^2}4.

You have r=2, so the definite integral is equal to \dfrac{2^2\pi}4=\pi.

Another way to verify this is to actually compute the integral. Let x=2\sin u, so that \mathrm dx=2\cos u\,\mathrm du. Now

\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx=\int_0^{\pi/2}\sqrt{4-(2\sin u)^2}(2\cos u)\,\mathrm du=4\int_0^{\pi/2}\cos^2u\,\mathrm du

Recall the half-angle identity for cosine:

\cos^2u=\dfrac{1+\cos2u}2

This means the integral is equivalent to

\displaystyle2\int_0^{\pi/2}(1+\cos 2u)\,\mathrm du=2u+\sin2u\bigg|_{u=0}^{u=\pi/2}=\pi
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3 years ago
1/2 of 4/5=1/2 of ___ fifth(s) = ___ fifth(s)
barxatty [35]

Answer:

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----                      ----

10 divided by 2= 5

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