1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irina1246 [14]
3 years ago
7

I 1/4 greater or less than 1/2

Mathematics
1 answer:
tangare [24]3 years ago
7 0
1 1/4 is greater than 1/2

There are 5- 1/4's in 1 1/4
There are 2- 1/4's in 1/2
You might be interested in
HURRY STRANGERS PLEASE I REALLY NEED THIS!!! A paper manufacturer is evaluating their packing procedures. Currently, they packag
drek231 [11]

Answer:

Step-by-step explanation:

Base on my own understanding what should be done is that three stacks will not work, because it wont be a symmetric arrangement and also one will be left out. So, two stacks of five each would be better and easy to carry. But the stacks should be arranged in such a manner that the lengths will be parallel to each other and not in-line which would increase the length making it comparatively very long. its easier to hold a (2*8.5,11,2*5=17,11,17) compact box, because it will be easy to carry a long and not heavy.

7 0
3 years ago
Plzzzzzzzzzz help me
Ierofanga [76]

The answer would be the top right graph where none of the lines intersect since it shows that there is no possible real solutions for the system if none of the lines intersect on a certain point.

Remember: If the lines intersect, there is a solution; if the lines do not intersect, there is no solution; if the lines fall on the same line, or the equations are equivalent, then the solution is all real numbers.

8 0
3 years ago
NEED HELP ASAP
VARVARA [1.3K]

When solving an equation with an absolute value term, you make two separate equations ans solve for x:

Equation 1: |4x-3|-5 = 4

1st add 5 to both sides:

|4x-3| = 9

Remove the absolute value term and make two equations:

4x-3 = 9 and 4x - 3 = -9

Solving for x you get X = 3 and x = -1.5

When you replace x with those values in the original equation the statement is true so those are two solutions.

Do the same thing for equation 2:

|2x+3| +8 = 3

Subtract 8 from both sides:

|2x+3| = -5

Remove the absolute value term and make two equations:

2x +3 = -5

2x+3 = 5

Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.

The answer is:

C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

3 0
3 years ago
I don't understand what to do. can u please answer these questions
MariettaO [177]
I believe you will need to find what -0.125 of an inch is, subtract that from 16, then divide that into 11.
6 0
3 years ago
Which properties of logarithms help you simplify log 200 + log 5 - log 100? (Select all that apply.)
bearhunter [10]

Answer:quotient property

Product property

Step-by-step explanation:

Just took the test

5 0
3 years ago
Other questions:
  • What’s the 10th term in 1,4,6,10
    8·1 answer
  • A rectangular garden is to be constructed using a rock wall as one side of the garden and wire fencing for the other three sides
    8·1 answer
  • Can you guys please help me out
    6·1 answer
  • Which is a quadratic function?
    15·1 answer
  • Domain and range help
    13·1 answer
  • Please teach me these question step by step. Thank you
    6·1 answer
  • What is the value of the median ? <br> 1. 8 <br> 2. 4 <br> 3. 6<br> 4. -4
    12·1 answer
  • PLEASE HELP IM NEW HERE! A library would like to see how many of its patrons would be interested in regularly checking out books
    14·1 answer
  • Visitors to the library restroom used up 3/4 of a bottle of soap in 1/2 of a day. At that rate, how much soap would they use up
    7·2 answers
  • In the triangles shown, ABC is dilated by a scale factor of to form XYZ. Given that mA = 45o and mB = 105o, what is mZ?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!