Answer:
Step-by-step explanation:
Base on my own understanding what should be done is that three stacks will not work, because it wont be a symmetric arrangement and also one will be left out. So, two stacks of five each would be better and easy to carry. But the stacks should be arranged in such a manner that the lengths will be parallel to each other and not in-line which would increase the length making it comparatively very long. its easier to hold a (2*8.5,11,2*5=17,11,17) compact box, because it will be easy to carry a long and not heavy.
The answer would be the top right graph where none of the lines intersect since it shows that there is no possible real solutions for the system if none of the lines intersect on a certain point.
Remember: If the lines intersect, there is a solution; if the lines do not intersect, there is no solution; if the lines fall on the same line, or the equations are equivalent, then the solution is all real numbers.
When solving an equation with an absolute value term, you make two separate equations ans solve for x:
Equation 1: |4x-3|-5 = 4
1st add 5 to both sides:
|4x-3| = 9
Remove the absolute value term and make two equations:
4x-3 = 9 and 4x - 3 = -9
Solving for x you get X = 3 and x = -1.5
When you replace x with those values in the original equation the statement is true so those are two solutions.
Do the same thing for equation 2:
|2x+3| +8 = 3
Subtract 8 from both sides:
|2x+3| = -5
Remove the absolute value term and make two equations:
2x +3 = -5
2x+3 = 5
Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.
The answer is:
C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
I believe you will need to find what -0.125 of an inch is, subtract that from 16, then divide that into 11.
Answer:quotient property
Product property
Step-by-step explanation:
Just took the test
