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Kamila [148]
3 years ago
5

Does (–1, 3) make the equation y = 7 true?

Mathematics
1 answer:
Llana [10]3 years ago
7 0

Answer:

no ............mmmmmmmmmm.

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Helppp what’s the answer
jarptica [38.1K]

Answer:

It is the 3rd option (going from left to right)

Step-by-step explanation:

7 0
3 years ago
a storage tank has the dimensions shown below how many storage tanks are needed to contain 60000 cubic meters of liquid
Sladkaya [172]
First find the volume of that container

R = pi (r)^2h
R = pi (15.21)(12.4)
R = 592.5169408

60,000 / R = 101.2629275

102 storage tanks
4 0
3 years ago
Mrs. Blair believes there is a relationship between the number of minutes students study and their test grades. She asked her hi
kodGreya [7K]

Answer:

I would say C 80. I'm not fully sure tho.

Step-by-step explanation:

Sorry If I'm late on this or If I'm wrong

4 0
2 years ago
Write the sentence as an equation.
bearhunter [10]

The solution to a given word problem by writing it as an equation is k = 253/232

<h3>Expressing word problems in mathematical forms:</h3>

The process of expressing word problems in mathematical forms takes a logical and chronological approach while taking the variables and arithmetic operations given into consideration.

From the given information, to express the word problem in mathematical form, we have:

  • 253 = 232 × k
  • 253 = 232k

Making k the subject of the equation, we have:

k = 253/232

Learn more about expressing word problems here:

brainly.com/question/10556265

#SPJ1

5 0
2 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m

f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0
4 years ago
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