Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
The answer would be 25.65
Answer:
0.09
Step-by-step explanation:
avg rate of change is: change in y/ change in x
so it´d be 3.59 - 0.89 / 2014 - 1984
= 2.7/ 30
= 0.09
note:
The slope formula and the average rate of change formula are the same, just written a bit different, so you could also use:
y2 - y1 / x2 - x1
It takes Selma 1/6 of a hour to run 3/4 miles.
Just multiply 3/4 by 6 to get 18/4 which is 4.5 miles or 4 1/2 mile
5 and 2/10 converted into decimal notation would be, 5.2
