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2 years ago

408 = 12x + 16y solve for both x and y?

Mathematics

1 answer:

Anon25 [30]2 years ago

4 0

Answer:

Slope= − 1.500/2.000

= -0.750

x intercept= 102/3

= 34

y−intercept= 102/4

= 51/2

= 25.50000

Step-by-step explanation:

sorry if this is wrong, I tried!

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Please someone help me with this problem?

yKpoI14uk [10]

X=B^1 + b^7 . i found my answer by you need to find the slope of the numbers between the table.

4 0

3 years ago

HELP PLEASE! FIND THE SURFACE AREA OF PYRAMID

Wittaler [7]

Answer:

136.73972

Step-by-step explanation:

A=lw+l(w

2)2+h2+w(l

2)2+h2=6·5.2+6·(5.2

2)2+92+5.2·(6

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2 years ago

Read 2 more answers

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$