The integration of the function f(x, y) = 2x²y³ from 0 to 3 with respect to x is 27y³.
<h3>What is integration?</h3>
It is the reverse of differentiation.
The function f(x, y) is given below.
f(x, y) = 2x²y³
Then the integration of the function from 0 to 3 with respect to x.
More about the integration link is given below.
brainly.com/question/18651211
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f(x) = x^3 + x^2 + 3x^0 is neither even nor odd. Why? Because we have a mixture of even and odd powers of x here: x^3 (odd) and x^2 and x^0 (even).
Even functions: all component functions are even (e. g., x^2 and x^0).
Odd functions: all component functions are odd (e. g., x^5 and x^3.
Neither: There's a mixture of even ad odd functions.
Another way to test for even, odd or neither:
Even functions: f(-x) = f(x). Changing the sign of the input (x) doesn't change the sign of the output.
Odd functions: f(-x) = -f(x). Changing the sign of the input changes the sign of the output.
Answer:
Step-by-step explanation:
So I'm looking at negative 64 and then four square to 16 and 16 times eight is 128 again May I'll show the steps you're subtracting off, you know, zero plus zero eso What we have is to native