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3 years ago

Solve the inequality -4y+6<-4

Mathematics

1 answer:

svet-max [94.6K]3 years ago

4 0

Answer:

y = 5/2

Step-by-step explanation:

-4y+6<-4 subtract 6 from both sides

-4y + 6 - 6 < -4 - 6 = -4y < -10 since both sides are negative we multiply it by -1 and get ➡ 4y < 10

Now divide both sides by 4

4y ÷ 4 < 10 ÷ 4 ➡ y < 5/2

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A company manufactures two types of electric hedge trimmers, one of which is cordless. The cord-type trimmer requires 2 hours to

Delvig [45]

There are commonly used four inequalities:

Less than = <

Greater than = >

Less than and equal = ≤

Greater than and equal = ≥

The inequalities that describe the constraints on the number of each type of hedge trimmer produced are:

x + y ≤ 200

2x + 10y ≤ 1000

<h3>What is inequality?</h3>

It shows a relationship between two numbers or two expressions.

There are commonly used four inequalities:

Less than = <

Greater than = >

Less than and equal = ≤

Greater than and equal = ≥

We have,

Total number of hours = 1000

Total number of trimmers = 200

Let x represent the number of cord-type models,

Let y represent the number of cordless models.

Now,

x + y ≤ 200

2x + 10y ≤ 1000

Thus,

The inequalities that describe the constraints on the number of each type of hedge trimmer produced are:

x + y ≤ 200

2x + 10y ≤ 1000

Learn more about inequalities here:

brainly.com/question/20383699

#SPJ1

6 0

1 year ago

zubka84 [21]

Answer:

See Explanation Below

Step-by-step explanation:

Given

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx.cos x.$

Required

Prove

To start with; we open the bracket on the left hand side

$(sin x - cos x)^2 = (sin x - cos x)(sin x - cos x)$

$(sin x - cos x)^2 = (sin x )(sin x - cos x)- (cos x)(sin x - cos x)$

$(sin x - cos x)^2 = sin^2 x -sinx cos x - sin xcos x + cos^2 x$

$(sin x - cos x)^2 = sin^2 x -2sinx cos x + cos^2 x$

Reorder

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

From trigonometry;

$sin^2x + cos^2x = 1$

So;

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

becomes

$(sin x - cos x)^2 = 1 - 2sinx cos x$

Also from trigonometry;

$sec^2x - tan^2x = 1$

So,

$(sin x - cos x)^2 = 1 - 2sinx cos x$

becomes

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx cos x$

Proved

3 0

3 years ago