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KATRIN_1 [288]
3 years ago
6

What is the interquartile range for this data set? 9, 17, 3, 26, 9, 15, 7, 20, 5, 12, 22

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0
23 because you subtract the highest from the lowest
stepan [7]3 years ago
4 0
23 because you subtract your highest number with your lowest number
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3 years ago
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Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3
lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 8.9

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 73.9}{8.9}

Z = 1.81

Z = 1.81 has a pvalue of 0.9649

X = 82

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 73.9}{8.9}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0
3 years ago
(x+40):12+78-88 exercitiul se face prin metoda mersului invers ajuor!
Mashutka [201]
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3 years ago
PLEASE HELP WILL MARK BRAINLIEST!
pav-90 [236]

Answer:

1, 5, 17, 53, 161

Step-by-step explanation:

Given:

  • a_1=1
  • a_n=3a_{n-1}+2

First five terms of the sequence:

a_1=1

a_2=3a_1+2=3(1)+2=5

a_3=3a_2+2=3(5)+2=17

a_4=3a_3+2=3(17)+2=53

a_5=3a_4+2=3(53)+2=161

7 0
2 years ago
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The area of a cylinder's base is 706.5 square millimeters. The cylinder's lateral area is 471 square millimeters. What is the to
Rzqust [24]
Just add the two bases plus the lateral area. so it would be 706.5+706.5+471.
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3 years ago
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