Answer:
The radius of sphere with volume 4500 cubic inches is 10.24 inches.
Step-by-step explanation:
Let V be the volume of the sphere
Given
Volume of sphere = V = 4500 cubic inches
Let r be the radius of the sphere
The volume of the sphere is given by the formula

Putting the known values

Taking cube root on both sides
![\sqrt[3]{r^3} = \sqrt[3]{1073.8636} \\r = 10.2403](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B1073.8636%7D%20%5C%5Cr%20%3D%2010.2403)
Rounding off to nearest hundredth
The radius is: 10.24 inches.
Hence,
The radius of sphere with volume 4500 cubic inches is 10.24 inches.
answer:
B. 0.01p + 0.05(22 – p) = 0.54
(got it correct on edgenuity)
Step-by-step explanation:
Answer:
............. ahi esta la respuesta
Given :

We know the identity
We use this property to simplify the left hand side
So 

we know ,
when
then

For 

Add
on both sides

Finally we add 2npi for general solution
So options C and D are correct
Answer:
t = 5 seconds h = 128 feet
Step-by-step explanation:
The given equation of the object is :
.....1
When it hits the ground,
h(t) = 0
So,

The object will hit the ground in 5 seconds.
Now, put t = 1 s in equation (1).

The object is at a height of 128 ft at 1 second.