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AlladinOne [14]
3 years ago
7

The length of a rectangle is seven units more than it's width if the width is doubled and the length is increased by two the are

a is increased by 42 square Units find the dimensiones of the original rectangle
Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0

Answer:

length = 10 units; width = 3 units

Step-by-step explanation:

Let the width = w

Then the length is w + 7

Original area: w(w + 7)

Double the width: 2w

Increase the length by 2: w + 9

Area of new rectangle: 2w(w + 9)

Area of new rectangle = w(w + 7) + 42

2w(w + 9) = w(w + 7) + 42

2w^2 + 18w = w^2 + 7w + 42

w^2 + 11w - 42 = 0

(w + 14)(w - 3) = 0

w + 14 = 0 or w - 3 = 0

w = -14 or w = 3

A width cannot be negative, so we discard w = -14.

The original width is 3 units.

The length is 7 more than the width, so the length is 10 units.

Anit [1.1K]3 years ago
5 0

yup the guy below me Is right

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