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djyliett [7]
2 years ago
7

Are sin and cosine graphs supposed to be curved (u-shape) or up and down (like a v-shape)?

Mathematics
2 answers:
hichkok12 [17]2 years ago
3 0
The graphs are curved, not segments ending in a point.


http://www.wolframalpha.com/input/?i=plot+y+%3D+sin+x+for+-3.2+%3C+x+%3C+3.2+and+-1.1+%3C+y+%3C+1.2

Leni [432]2 years ago
3 0
Cosine graphs and sine graphs have more of a u-shaped form instead of a sharp v shape. 
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The answer is c, or 3b+6!!
7 0
3 years ago
In right triangle abc /_B is right angle and m/_c=30 if Ac=10 what is AB
Ivanshal [37]

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plz mark brainliest..

Step-by-step explanation:

AC is the hypotenuse = 10

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7 0
3 years ago
Match the information on the left with the appropriate equation on the right.
zaharov [31]

Answer:

See attachment below

Step-by-step explanation:

For the first option, we are given m = - 2 / 3, b = 3. This is likely in the point - slope form y = mx + b, where m = slope and b = y - intercept. Thus, the equation of the line in point - slope form given this information, should be y = - 2 / 3x + 3. It seems as if none of the following equations match this form, so let us interchange the equation a bit,

y = - 2 / 3x + 3,

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2x + 3y = 9 - Option C

_______________________________________________________

Next we are given m = - 3 / 2, and that this line passes through the point ( 4, - 1 ). Substitute m as - 3 / 2, x as 4, y as - 1, knowing point ( 4, - 1 ), into the form y = mx + b - solving for b.

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y = - 3 / 2x + 5,

2y = - 3x + 10,

- 2y = 3x - 10 - Option A

_______________________________________________________

( 6, 3 ) and ( 3, 1 ) is given to lie on this line. The slope of the line should be as follows,

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Now let us determine the y - intercept ( b ) by substitute one of the points, say ( 6, 3 ). In this case x = 6, and y = 3,

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Take a look at the attachment below for further help;

6 0
2 years ago
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