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zalisa [80]
3 years ago
7

How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C

TTACAGTTTATTGATACGGAGAAGG... 3' 3'... GAATGTCAAATAACTATGCCTCTTCC... 5'

Biology
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios)  for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3'  NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3'  NO STOP CODON

5'... CTT ACA GTT TAT <u>TGA</u> TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG <u>TAA</u> G

4)Now you need to find start (AGT in terms of DNA) and stop codons(<u>TAA</u>, <u>TAG,</u> <u>TGA</u>, also in terms of DNA), in 5->3 and de reverse complementary.

<em />

<em>As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.</em>

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

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Answer:

2001

Explanation:

This question showcases a table that displays Mendel's results (figures) when he crossed pea plants and observed different characters in the plant. Mendel worked with different phenotypic characteristics in the pea plant.

According to the table, the result were for seven characteristics including height, flower color, flower position, pod color, pod shape, seed color, seed shape. Based on the observation of the number of F2 offsprings that possessed dominant trait and recessive trait for each character, we will notice that it follows an approximate phenotypic ratio of 3:1

1. Plant height 787 tall 277 short (3:1)

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This 3 dominant : 1 recessive ratio is the ratio got in the F2 offsprings when he observed the seven characteristics in pea plants. Hence, the seed color will also follow the same 3:1 ratio

Therefore, 2001 is the result Mendel obtained in the F2 offsprings for the recessive trait of seed color characteristics in his experiment, which actually depicts the 3:1 ratio. Hence, X (green seed color) is 2001

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