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balu736 [363]
3 years ago
9

Please help me! I need an answer as soon as possible!

Mathematics
1 answer:
blagie [28]3 years ago
6 0

Answer:

It should just be the radius

Step-by-step explanation:

The radius is half the diameter of the circle and all you’re doing is taking the radius multiple times

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Find the seventh term of the
jekas [21]

Answer:

T_7 = \frac{64}{729}

Step-by-step explanation:

Given

a =1

r = \frac{2}{3}

Required

Determine the 7th term

The nth term of a gp is:

T_n = a * r^{n-1

So, we have:

T_7 = 1 * \frac{2}{3}^{7-1

T_7 = 1 * \frac{2}{3}^{6

T_7 = 1 * \frac{2^6}{3^6}

T_7 = 1 * \frac{64}{729}

T_7 = \frac{64}{729}

6 0
3 years ago
If 4x-1=X, Find 30x<br> a) 10 b) 40<br> C) 12 d)11<br><br> How do you solve this?
cestrela7 [59]

Answer:

(a)

Step-by-step explanation:

Given

4x - 1 = x ( subtract x from both sides )

3x - 1 = 0 ( add 1 to both sides )

3x = 1 ( multiply both sides by 10 )

30x = 10 → (a)

3 0
3 years ago
Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤
MrMuchimi
The average rate of change of a function f(x) in an interval, a < x < b is given by
\frac{f(b) - f(a)}{b - a}

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by \frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by \frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by \frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by \frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by \frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by \frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0
3 0
3 years ago
Read 2 more answers
Pls answer 3/ 5 + 2 = 2 /3
Zinaida [17]

Answer:

3/5+2 does not equal 2/3

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
Read 2 more answers
The graph represents this system of equations.
bonufazy [111]

Answer:

The answer to your question is (1, -2)

Step-by-step explanation:

See the graph below, in the graph, the solution is circled (1, -2). The solution is the point where the lines cross.

To check the answer, let's solve the system using algebra.

                                    y = 2x - 4

                                    y = 1 - 3x

                                  2x - 4 = 1 - 3x

                                  2x + 3x = 1 + 4

                                          5x = 5

                                            x = 5/5

                                            x = 1

Find y by substitution

                                   y = 2(1) - 4

                                   y = 2 - 4

                                   y = -2

Solution

                                    (1, -2)            

5 0
3 years ago
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