The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :


We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
brainly.com/question/10633821
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The last term is -100 so its either a or d.
Try a:-
(x^2 - 25)(x-2)(x - 2)
= x^2 - 25 (x^2 - 4x + 4)
= x^2 + 4x^3 + 4x^2 - 25x^2 + 100x - 100
= x^4 + 4x^3 - 21x^2 + 100x - 100
Its a.
bruh
why
what
?
osea si pero al a vez cuando pasa osea si parece pero no lo es pero lo es cuando puede ser
The answer is a (three eights over three fifths= five eights)