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Sidana [21]
3 years ago
11

Subtract u from the sum of s and t

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

(s+t)-u

Step-by-step explanation:

You have to add s and t.

Since they are variables, the sum will be s+t

you then have to subtract u from s and t so, you have (s+t)-u

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Suppose C and D represent two different school populations where C &gt; D and C and D must be greater than 0. Whitch of the foll
In-s [12.5K]

Answer:

<em>A. (C+D)^2  is the largest expression</em>

Step-by-step explanation:

<u>Squaring Properties </u>

The square of a number N is shown as N^2 and is the product of N by itself, i.e.  

N^2=N*N

If N is positive and less than one, its square is less than N, i.e.

N^2

If N is greater than one, its square is greater than N

N^2>N, \ for\ N>1

We have the following information: C and D represent two different school populations, C > D, and C and D must be positive. We can safely assume C and D are also greater or equal than 1. Let's evaluate the following expressions to find out which is the largest

A. (C+D)^2

Expanding  

(C+D)^2=C^2+2CD+D^2

Is the sum of three positive quantities. This is the largest of all as we'll prove later

B. 2(C+D)

The extreme case is when C=2 and D=1 (recall C>D). It results:

2(C+D)=2(3)=6

The first expression will be

(3)^2=9

Any other combination of C and D will result smaller than the first option

C. C^2 + D^2

By comparing this with the first option, we see there are two equal terms, but A. has one additional term 2CD that makes it greater than C.

D. C^2 - D^2

The expression can be written as

(C+D)(C-D)

Comparing with A.

(C+D)^2=(C+D)(C+D)

The subtracting factor (C-D) makes this product smaller than A which has two adding factors.

Thus A. is the largest expression

7 0
3 years ago
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