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Yakvenalex [24]
3 years ago
8

Find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success i

s 40%.
Mathematics
1 answer:
DiKsa [7]3 years ago
6 0

0.45033504848

Explanation:

The binomial formula is given by
<span>nCk⋅<span>ρk</span><span><span>(1−ρ)</span><span>n−k</span></span></span> thus the result for x would be

<span>p<span>(x=2)</span>=<span>(<span><span>5!</span><span><span>(5−2!)</span>2!</span></span>)</span><span><span>(.4)</span>2</span><span><span>(1−.4)</span><span>5−2</span></span>=0.3456</span>

<span>p<span>(x=3)</span>=<span>(<span><span>5!</span><span><span>(5−3!)</span>3!</span></span>)</span><span><span>(.4)</span>3</span><span><span>(1−.4)</span><span>5−3</span></span>=0.13824</span>

<span>p<span>(x=4)</span>=<span>(<span><span>5!</span><span><span>(5−4!)</span>4!</span></span>)</span><span><span>(.4)</span>4</span><span><span>(1−.4)</span><span>5−4</span></span>=0.027648</span>

<span><span>p<span>(a∪b∪c)</span>=p<span>(a)</span>+p<span>(b)</span>+p<span>(c)</span>−p<span>(a)</span>⋅p<span>(b)</span>−p<span>(a)</span>⋅p<span>(c)</span>−p<span>(b)</span>⋅p<span>(c)</span></span><span>=.3456+.13824+.027648−.047775744−.0095551488−0.00382205952</span></span>

<span>p<span>(a∪b∪c)</span>=<span>0.45033504848</span></span>

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